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HomeMy WebLinkAbout2700 W 25th St 02-1918 (anti-float computation)INTERPLAN 933 LEE ROAD, FIRST FLOOR ORLANDO, FL 32810 PH 407.645.5008 FX 407.629.9124 7 -Eleven Store # 25882 2700 West 25th Street Sanford, Florida I.P. # 2001.2001 Anti -Flotation Computation SEM!NOLE COUNTY TANKS BUREAU PLAN REVI p BY TANKS/ LINES ONLY For (2) 10,000 gal double wall fiberglass tanks 8 ft. in diameter and 31'- 6.5" long (reference attached drawings) 2. 3 Assumptions a) Wet season water table at ground surface. b) Weight of pumps and equipment is ignored. C) Weight of concrete 150#/CF submerged 87.6#/CF d) Weight of soil 100#/CF submerged 60#/CF Upward Force: Volume Displaced (two tanks) (Shipping weight 4,085# or weight w/brine 5,664#) V = 10,000 gal 7.48ga1/CF V„ = 1337 CF x 2 = 2674 CF F = 2674 CF x 62.4#/CF = 166,858# f.s. =1.1 x 166,858 = 183,544# Downward Force a) Weight of tanks =5,664 x b) Weight of slab over tanks 41 x 31 x 8/12 x 87.6 = FAS-W-Eleven\2001.2001\2001 calcs.doc 2 - 10,000 gal tks L=31'-6.5" D = 8' Total Upward Force = 183,544# 2 11,328# 74,219# ARCHITECTURE ■ ENGINEERING - PROJECT MA EMENT ■ INTERIOR DESIGN ■ AA 003420 - CA 8660 development services for restaurant, retail, hospitality and commercial programs - www.interplanorlando.com INTERPLAN LLC C) Volume of overburden (two tanks) Where: B, = 31.5 x 18 = 567 SF Bz = 41 x 31 = 1271 SF V = (h/3) (131 + BZ + 4B, x Bz) - (V/2) V = (6.83/3) [(567) + (1271) +4(567 x 1271)] - 1337 x 2 2 V = 4780 CF Force = 4780 CF x 60#/CF = 286,812# d) Weight of deadman For two (2) 10,000 gallon tanks Outer deadman 8 - 1 x 1 x 16 = 128 x 87.6#/CF = 11,212# Total Downward Force = 383,571# Net Downward Force = 200,027# f.s. 2.09 No additional tie downs required. FAS-Z\7-Hleven\2001.2001 MO 1 calcs. doc development services for restaurant, retail, hospitality and commercial programs ■ www.interplanorlando.com